Mol Ratio of Na2CO3 + HCl Reaction

In summary, the mol ratio of Na2CO3 and HCl in this reaction is 1:2. To calculate the mol ratio, the number of moles of each substance must be determined and then divided. The mol ratio is important because it determines the amount of each substance needed for the reaction to occur completely. It also directly affects the amount of product formed in the reaction. The mol ratio can be changed by altering the amount of each substance used, but it is crucial to maintain the correct ratio for the reaction to proceed efficiently.
  • #1
xxpsychoxx
16
0
Im a beginner in chemistry and i just did a chemistry lab with my class on titration.
Na2CO3(s) + 2HCl(aq)==>2NaCl(aq) + CO2(g) + H2O(l)
Can any1 tell me what the mol ratio is for this equation?
 
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  • #2
The balanced equation tells you the mole ratio. eg. You know that 1 mole of Na2CO3 reacted with 2 moles of HCL
 
  • #3


The molar ratio for this equation is 1:2. This means that for every 1 mole of Na2CO3 that reacts, 2 moles of HCl are needed. This can also be seen in the balanced equation, where the coefficient of Na2CO3 is 1 and the coefficient of HCl is 2. This molar ratio is important in determining the amount of reactants needed for a given amount of product, as well as in calculating the theoretical yield of the reaction.
 
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