2.8 g of NaCH3COO is dissolved into an unknown volume. The resulting concentration produced is 4.3 * 10-2 M, what volume of water was used?
c = n/V
The Attempt at a Solution
I[/B] calculated molar mass of the NaCH3COO as 82.0 g/mol, which is 0.034 mol. I then used the c = n/V equation.
4.3 * 10-2 M = 0.034 mol / V
V = 0.79 L
Where I am confused now is if that is the volume of the solution, or of the water? I think it's the volume of solution, and am not sure how to calculate the water.