Molar Specific Heat

  • Thread starter G-reg
  • Start date
  • #1
44
0

Homework Statement


A certain substance has a mass per mole of 55 g/mol. When 284 J is added as heat to a 32.0 g sample of this material, its temperature rises from 22.0°C to 39.5°C

And I know that the specific heat of this substance is 507.14 J/[kg(K)]


Homework Equations



Q = mc[tex]\Delta[/tex]T


The Attempt at a Solution



55 g/mol * (1/32g) = 1.71875mol

284J/[(1.71875mol)/(39.5-22)] = 9.44 J/[mol(K)]

however..this is wrong and now I'm not sure where to go..help pleeeease!
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,223
31

Homework Statement


A certain substance has a mass per mole of 55 g/mol. When 284 J is added as heat to a 32.0 g sample of this material, its temperature rises from 22.0°C to 39.5°C

And I know that the specific heat of this substance is 507.14 J/[kg(K)]

I assume you used the information to find that.

[tex]c= 507.14 \frac{J}{kgK}[/tex]


for the substance, 1 mol has how much mass in kg?
 

Related Threads on Molar Specific Heat

  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
2
Views
9K
Replies
4
Views
586
  • Last Post
Replies
2
Views
7K
  • Last Post
Replies
4
Views
6K
Replies
15
Views
274
Replies
5
Views
4K
Replies
7
Views
1K
Top