symbolipoint said:How many moles compound in each trial? How much volume of finished solution in each trial? Calculate the ratio.
The total volume is 7.00 mL. Is that how much volume of finished solution would be in each trial?
TypeFun said:I'm still struggling.
I've calculated the grams of Na2S2O3 = 1.58 g, but I'm still confused as to how I get the molarity of S2O3
Molarity is a unit of concentration that measures the number of moles of a solute in a liter of solution. It is expressed in units of moles per liter (mol/L) or sometimes as molar (M).
Molarity is calculated by dividing the number of moles of solute by the volume of the solution in liters. This formula is expressed as M = moles of solute / liters of solution.
Molality is a unit of concentration that measures the number of moles of solute per kilogram of solvent, while molarity measures the number of moles of solute per liter of solution. Molality is often used at high temperatures or in situations where the volume of the solution may change.
Yes, you can convert between molarity and molality using the formula Molarity = Molality x Density x Molecular Weight. However, this conversion only works for dilute solutions and at a constant temperature.
Molarity is used in stoichiometry calculations by converting the given molarity of a solution into moles of solute, and then using the mole ratio from the balanced equation to determine the moles of the other reactants or products involved. These moles are then converted back into molarity to find the concentration of the final solution.