Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Molarity of solution

  1. Jan 13, 2004 #1
    Is this how you work this problem:

    A sulfuric acid solution has a density of 1.49 g/mL and contains 59 percent H2SO4
    by mass. what is the molarity of this solution?

    .59x98g = 57.82g H2SO4
    1mL/1.49g x 57.82g H2SO4 = .0388L

    57.82g H2SO4/ 98g H2SO4 = .59 mol

    .59 mol/.0388L = 15.206 M H2SO4
  2. jcsd
  3. Jan 14, 2004 #2
    Now molarity is defined as number of moles of solute per litre of solution.

    Now for this wt of solution is= density*Volume =1.49*1000

    calculate 59% of this which gives the weight of H2SO4 in solution of 1000mL Divide it by 98 to get the molarity
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?