- Mole and Avogadro's Number -

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  • #1
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2.95 mol Ba(OH)4 to atoms. (I think I wrote this problem wrong. It might be (OH)2 instead).
I'm confused >.< Do I:
1) multiply 2.95 mol by 6.02 x 10^23 atoms or
or
2) multiply 2.95 mol x 6.02 x 10^23 molcules x 9 atoms.
or is it something else?

Also, how do I do these?
Calculate the mass of 3.01 x 10^23 formula units (ions) of Strontium hydroxide.
Find the number of atoms in 16.0g of sulfur

Please help if you can. ~____~
 
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  • #2
eax
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moles is amount of particals. When this compound is broken down it is split into 1Ba and 4(OH) [according to you].

moles * 6.02E23= number of particals
(Number of particles)*(Number of particles the molecule can decompose to)=number of ions of that particular particle.
 
  • #3
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eax said:
moles is amount of particles.
hence no. of molecules=2.95*6.023*10^23
hence no. of atoms= no. of molecules*no. of atoms per molecule(9 in your case, though it is Ba (OH)2, i.e. 5):smile:
Strontium hydroxide is Sr (OH)2
hence no. of formula units= no. of atoms
hence mass = (molarmass/avogadro's no.)*no. of units
same for next.
refer University Chemistry by Bruce Mahan for details.
 
  • #4
GCT
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if they're asking for the atoms of Ba(OH)2 and not its constituent ions, then you would simply solve this by factor labeling

2.95mol Ba(OH)2(6.022x10^23 molecules Ba(OH)2/1mol Ba(OH)2) =?, you should verify that the units cancel out during such processes
 

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