1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Mole equation

  1. Nov 14, 2009 #1
    8. In the processing of uranium, one of the steps involves converting UO2 to UF6.

    UO2(s) + 4HF(g) + F2 (g) --> UF6 (g) + 2H2O (l)

    For 7.50kg of UO2, calculate:

    a) The mass of hydrogen fluride required.
    m(UO2) = 7500g
    n(UO2) = 27.78mol

    n(UO2) = n(HF)
    27.78mol =

    m(HF) = 27.78*39.008
    = 1083.64g

    b) The mass of fluorine required

    n(UO2) = 2n(F2)
    27.78mol =
    27.78*2 =
    55.56mol =

    m(F2) = 1055.6g or 1.06x10^3g

    c) The mass of UF6 produced.

    With question (C) could you please do it and explain the mole ratio to me, as when i did it i did a mole ratio of n(UO2) = n(UF6) but the answer makes it seem that it's n(UO2) = 4/3n(UF6).

    Thanks, Sirsh.
  2. jcsd
  3. Nov 15, 2009 #2


    User Avatar

    Staff: Mentor




    That's OK, correct answer is slightly below 10 kg.

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook