Mole fraction

  • Thread starter mikep
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does anyone know how to do this problem?
The total vapor pressure above a solution of [tex]C_6H_6(l)[/tex] and [tex]C_7H_8(l)[/tex] is 0.485 atm. What is the mole fraction of [tex]C_6H_6(l)[/tex] in the liquid solution?
[tex]P^o C6H6(l) = 0.526 atm[/tex]
[tex]P^o C7H8(l) = 0.188 atm[/tex]

the answer is 0.879 but i'm not sure how to get that using the formula [tex]P_A = (X_A)(P^o _A)[/tex]
 
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  • #2
Gokul43201
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mikep said:
does anyone know how to do this problem?
The total vapor pressure above a solution of [tex]C_6H_6(l)[/tex] and [tex]C_7H_8(l)[/tex] is 0.485 atm. What is the mole fraction of [tex]C_6H_6(l)[/tex] in the liquid solution?
[tex]P^o C6H6(l) = 0.526 atm[/tex]
[tex]P^o C7H8(l) = 0.188 atm[/tex]

the answer is 0.879 but i'm not sure how to get that using the formula [tex]P_A = (X_A)(P^o _A)[/tex]
It's a direct substitution problem.

[tex]P_{tot} = P_A + P_B = (X_A)(P^o _A) + (X_B)(P^o _B) = (X_A)(P^o _A) + (1-X_A)(P^o _B)[/tex]

Now just plug in the given numbers and solve for [itex]X_A [/itex]
 

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