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**"How many litres of air (78% N2, 22% O2 by volume) are needed for the combustion of 1 litre of octane, C8H18, a typical gasoline component, of density 0.70g/mL?"**

Note - 1 mole of oxygen gas is equal to 24.5 litres.

Note - 1 mole of oxygen gas is equal to 24.5 litres.

I have done the chemical equation of the combustion of octane which is C8H18 + 25/2O2 ---> 8CO2 + 9H20 but I am unsure about what to do next.

Thank you