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Homework Help: Molecular Weight

  1. Dec 6, 2011 #1
    1. A 0.0097561 g quantity of an unknown gas occupies 0.2 L at 500 K and 2 atm. What is the Molecular Weight (MW) of the gas ?



    2. PV = nRT



    3. mw=0.0097561*0.082*500/2*0.2
    mw=1
     
  2. jcsd
  3. Dec 6, 2011 #2
    Your answer is right, although it would be nice to see some work shown in case there are any minor errors that could be caught.
     
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