# Molecular Weight

1. Dec 6, 2011

### gwiber

1. A 0.0097561 g quantity of an unknown gas occupies 0.2 L at 500 K and 2 atm. What is the Molecular Weight (MW) of the gas ?

2. PV = nRT

3. mw=0.0097561*0.082*500/2*0.2
mw=1

2. Dec 6, 2011

### ptolema

Your answer is right, although it would be nice to see some work shown in case there are any minor errors that could be caught.