Calculating Fe2O3 Reactivity with Fe

[toughguy]

How can you calculate how many grams of Fe2O3 must react with 0.57 mol of Fe when given the formula:
Fe2O3 + 3CO = = = => 2Fe + 3CO2

 

[Hootenanny]

How can you calculate how many grams of Fe2O3 must react with 0.57 mol of Fe when given the formula:
Fe2O3 + 3CO = = = => 2Fe + 3CO2

Have you any thoughts of your own?

 

[Blueshift5]

To calculate the amount of Fe2O3 needed to react with 0.57 mol of Fe, we can use the balanced chemical equation and the molar ratio between Fe2O3 and Fe. From the equation, we can see that for every 2 moles of Fe2O3, 2 moles of Fe are produced. This means that the molar ratio between Fe2O3 and Fe is 1:1.

To determine the amount of Fe2O3 needed, we can use the following formula:

n = moles of Fe x (1 mole Fe2O3 / 1 mole Fe)

Substituting the given values, we get:

n = 0.57 mol Fe x (1 mol Fe2O3 / 1 mol Fe)

n = 0.57 mol Fe2O3

To convert this to grams, we can use the molar mass of Fe2O3, which is 159.69 g/mol.

Therefore, the amount of Fe2O3 needed to react with 0.57 mol of Fe is 0.57 mol x 159.69 g/mol = 91.13 grams of Fe2O3.

It is important to note that this calculation assumes ideal conditions and complete reaction, so the actual amount of Fe2O3 needed may vary depending on the experimental conditions.