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Moles ratio homework

  1. Nov 19, 2009 #1
    1. The problem statement, all variables and given/known data

    Given:

    (1/2) mol N2 + (3/2) mol H2 -> NH3 change in H = -46.11 kJ/mol

    If the number of moles of N2 are changed to 10 and the number of moles of H2 to 35,
    how much heat is generated if only 10% of the Nitrogen reacts?


    3. The attempt at a solution

    After setting up a ratio, I find that 10 moles of N2 can produce 20 moles of NH3. Thus, 10% of the N2 means 10% of the NH3, so 2 moles of NH3 are produced.

    I multiple 2 by the original energy to achieve -92.22kJ.

    Did I do this correctly?
     
  2. jcsd
  3. Nov 26, 2016 #2

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    Appears to be correct.
     
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