How can I determine the force at support B in a rigid bar system?

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In summary, The question asks to find the force acting at support B. The sum of clockwise moment and the sum of anticlockwise moment are equal. The answer can be obtained by adding all the forces together. The pivot point is not necessary to calculate the force at B. The sum of vertical forces must be 0 for the system to be static, and the force at B can also be determined by taking moments about any point on the line except B.
  • #1
coconut62
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Homework Statement



Please refer to the image.

Homework Equations



Sum of clockwise moment=sum of anticlockwise moment

The Attempt at a Solution



I had drawn out the force diagram and listed out the information required.

The question asks me to find force acting by the support B.

I troubled myself by taking moments about A and multiplying every forces with their respective distances from A.

However the answer was simple, they just added all other forces together, 33 + 4.4 + 129 = 166N.

I can't figure out where is the pivot. Or is there even a pivot? What's the theory behind this calculation?
 

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  • #2
But how was the 129N figure obtained? You'd need to take moments to derive that.
 
  • #3
Haruspex, the 129N is obtained from another part of the question which is correct.
 
  • #4
coconut62 said:
Haruspex, the 129N is obtained from another part of the question which is correct.
Then it is indeed simple to determine the force at B in the way they use. For the system to be static, the sum of the vertical forces must be 0. You could also deduce it by taking moments about anywhere along the line except B.
 
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As a scientist, the force at support B in a rigid bar system can be determined by using the principle of moments. This principle states that the sum of clockwise moments is equal to the sum of anticlockwise moments in a system at equilibrium. In order to determine the force at support B, we need to find the point where the system is in equilibrium, or where the sum of moments is equal to zero.

To do this, we first need to identify all the forces acting on the system and their respective distances from the point of interest, which in this case is support B. In the given image, we can see that the forces acting on the system are 33N, 4.4N, and 129N. We also know that the distance between support B and the point where the 33N force is acting is 3m, the distance between support B and the point where the 4.4N force is acting is 1.5m, and the distance between support B and the point where the 129N force is acting is 2m.

Next, we can apply the principle of moments by setting up an equation where the sum of clockwise moments is equal to the sum of anticlockwise moments. This can be written as:

(33N x 3m) + (4.4N x 1.5m) + (129N x 2m) = 0

Solving for the unknown force at support B, we get:

(33N x 3m) + (4.4N x 1.5m) + (129N x 2m) = FB x 0

Therefore, FB = (33N x 3m) + (4.4N x 1.5m) + (129N x 2m) / 0

FB = 166N

This means that the force at support B is 166N, which is the sum of all the other forces acting on the system. This calculation is based on the principle of moments, which is a fundamental concept in mechanics and is used to solve problems involving forces and torques in a system at equilibrium.
 

1. What is the moment about a rigid bar?

The moment about a rigid bar is a measure of the tendency of a force to cause a rotation about a specific point on the bar. It is also known as torque and is measured in units of force multiplied by distance, such as Nm or lb-ft.

2. How is the moment about a rigid bar calculated?

The moment about a rigid bar is calculated by multiplying the force applied to the bar by the distance between the force and the point of rotation. This distance is known as the lever arm and is measured perpendicular to the direction of the force.

3. What is the difference between a positive and negative moment about a rigid bar?

A positive moment about a rigid bar indicates a tendency to cause a counterclockwise rotation, while a negative moment indicates a tendency to cause a clockwise rotation. This is based on the right-hand rule, where the fingers point in the direction of the force and the thumb points in the direction of rotation.

4. How does the distribution of forces affect the moment about a rigid bar?

The distribution of forces along a rigid bar can affect the overall moment by changing the lever arm. When forces are evenly distributed, the resulting moment is zero. However, when there is an imbalance in the distribution, the moment will be non-zero and will depend on the magnitude and location of the forces.

5. What are some real-world applications of the moment about a rigid bar?

The concept of moment about a rigid bar is used in many engineering and physics applications. For example, it is essential in designing structures such as bridges and buildings to ensure they can withstand external forces and maintain stability. It is also crucial in understanding the mechanics of machines and tools, such as wrenches and levers, and how they can be used to exert a desired force. Additionally, moments are used in the study of rotational motion and angular momentum in physics.

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