- #1

- 11

- 0

A chiropractor performs a lumbar spinous pull manipulative procedure. Using instrumentation , she determines 3D coordinates of the axis of rotation of the contacted verebra at t = 15 msec relative to the local axis system as shown. A uniaxial load cell at the spinous process measures a force of Fs = 54.8 N during the thrust also at t = 15 msec. An optotrak camera system determines the 3D coordinates of two points along the line of force application relative to the local axis system again at t = 15 msec. All coordinate data (measured in metres as X, Y, Z) is shown below. Calculate the moment about the axis AB generated by the thrust at t = 15 msec. Assume bone acts as a rigid body.

Given: Point A along the axis of rotation: (.025, .134, .012)

Point B along the axis of rotation: (-.044, -.280, .048)

Point C at the spinous process: (-.003, -.032, -.082)

Point D along the line of force application: (.030, -.031, -.094)

okay i found this questions and have tried to figure it out. i know in theory what to do

1: calculate moment about a

get direction of c-d then get dc.

get length by pythagoreans and divide.

multiply by each component.

get position vector.

then i have force vector need to get cross product.

get moment about a-b figure out vector and need to know direction.

head-tail divide by length then have unit vector do cross product.

so i started to get moment about a.

i took all co-ordinates from a and got three co-ordinates for b,c and d. i multiplied all these co-ordinates by force 54.8 i added all co-ordinates and got -5.1 nm.

im just not sure i did the right thing. i dont want to move on until i know im on the right track.

any help would be appreciated

thanks

Given: Point A along the axis of rotation: (.025, .134, .012)

Point B along the axis of rotation: (-.044, -.280, .048)

Point C at the spinous process: (-.003, -.032, -.082)

Point D along the line of force application: (.030, -.031, -.094)

okay i found this questions and have tried to figure it out. i know in theory what to do

1: calculate moment about a

get direction of c-d then get dc.

get length by pythagoreans and divide.

multiply by each component.

get position vector.

then i have force vector need to get cross product.

get moment about a-b figure out vector and need to know direction.

head-tail divide by length then have unit vector do cross product.

so i started to get moment about a.

i took all co-ordinates from a and got three co-ordinates for b,c and d. i multiplied all these co-ordinates by force 54.8 i added all co-ordinates and got -5.1 nm.

im just not sure i did the right thing. i dont want to move on until i know im on the right track.

any help would be appreciated

thanks