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## Homework Statement

See attached image file

## Homework Equations

law sine

law cosine

## The Attempt at a Solution

Find the reactions about two points from the applied force at point B

Bx = 200Cos60 = 100N

By = 200Sin60 = 173.20N

May = -173N(.4m) + CyN(.15m) = 0

May = -461.86Nm

Max = -100N(.3) = -30Nm

Ma = -491.86Nm

I tried solving to find reaction at a, but not 100% if my result is correct. Any help would be appreciated