when you calculate the Moment of the following equation(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

p(x)=\left\{\begin{array}{cc}2Axe^{-Ax^2},&\mbox{ if }

x\geq 0\\0, & \mbox{ if } x<0\end{array}\right.

[/tex]

We get

[tex]

Mn =2A \int_0^\infty x^{n+1}e^{-Ax^2}

[/tex]

solving it by parts I am getting

[tex]

Mn=(n+1)\int_0^\infty x^{n-1}e^{-Ax^2}

[/tex]

but, apparently, the right solution is

[tex]

Mn=n\int_0^\infty x^{n-1}e^{-Ax^2}

[/tex]

What am I doing wrong? What is the proper way to solve it? Could you please do it step by step?

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Moment of a probability distribution

Loading...

Similar Threads for Moment probability distribution |
---|

I Looking for additional material about limits and distributions |

A Angular Moment Operator Vector Identity Question |

A Continuous mass distribution |

**Physics Forums | Science Articles, Homework Help, Discussion**