I have a 3-4-5 right triangle with the 3 as the base and the 5 as the hypotenuse.
The corner of the 3 and the 5 is point A
The corner of the 3 and the 4 is point B
At B, perpendicular to the base is a force of 100lb going down- into the corner. (Fv)
At B, Parallel to the base is a force of 100lb going "into" the corner. (Fh)
The question is asking: Find the moment of the force with respect to A.
The Attempt at a Solution
I am assuming the angles are 53 deg at A, 37 deg at B (and the 90 of course).
I am treating this like a torque equation but since the forces are going into the figure. I have no idea where to start. Any help would be greatly appreciated. It's been about 5 yrs since I have done any physics. I am taking a fluid dynamics class to prepare to begin getting my MS in Environmental Engineering (Water) in the fall.