1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Moment of Inertia and KE

  1. Mar 8, 2017 #1
    1. A 3.0 kg vertical rod has a length of 80 cm. A 4.0 kg rectangle attached to the top of the rod has negligible dimensions. The entire object rotates counterclockwise about the bottom of the rod. Determine the angular speed of the apparatus at the instant the rod is horizontal.


    2. Using energy --> mgh = .5Iωω --> ω= √(2mgh/I)


    3. I tried to use the parallel axis theorem to solve for I. I got 1.28. This would give me ω=√(2*7*9.8*.8/1.28) = 6.25 rad/s. I have used I= (1/12)(3)(.8*.8) + (3)(.4*.4) + (4)(.4*.4) plus several different variations.
     

    Attached Files:

  2. jcsd
  3. Mar 8, 2017 #2
    Where is the effective mass of the rod? How far does it fall?
     
  4. Mar 8, 2017 #3
    I think I have I have it figured out - I needed to use the center of gravity for my height in the mgh part of the problem --> so h = .625m not .4m, which is what I was doing before. Thanks!
     
  5. Mar 8, 2017 #4
    Are you sure it's 0.625 m?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Moment of Inertia and KE
  1. Moment of Inertia (Replies: 2)

  2. Moment of Inertia (Replies: 1)

Loading...