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Moment of Inertia Graph

  1. Nov 18, 2014 #1
    1. The problem statement, all variables and given/known data

    The moment of inertia (I) of the bicycle wheel about the axle, can be obtained graphically using the equation:
    rm(g-a) = I(a/r)+Frictional Torque. Explain how to form two variables so that, I and Frictional Torque can be obtained from a linear graph. Identify the constants corresponding to the slope and intercept of the proposed linear graph.

    r = 0.018m
    m=0.200kg
    g=9.8m/s^2
    a=0.002812
    I=?
    Frictional Torque= ?
    2. Relevant equations

    (1) rm(g-a) = I(a/r)+Frictional Torque.

    (2) y=mx+b

    3. The attempt at a solution

    Im not sure if im 100% right on this but, equation one could take the form of equation two.
    m being I.
    x being whats changing, ie. acceleration
    b being the y intercept, ie frictional torque

    Just unsure where to go from there a how to graph it.
     
    Last edited by a moderator: Nov 18, 2014
  2. jcsd
  3. Nov 19, 2014 #2

    haruspex

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    Presumably these variable relate to a physical set-up of some kind. Please describe it.
     
  4. Nov 20, 2014 #3

    andrevdh

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    The two variables are m and a. Try and rewrite the equation so that they become the x and y variables in the linear equation (or a combination of the variables!). The frictional torque and moment of inertia should then part of gradient and y-intercept values (r and g will also appear in these).
     
    Last edited: Nov 20, 2014
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