# Moment of Inertia Graph

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1. Nov 18, 2014

### cam borrett

1. The problem statement, all variables and given/known data

The moment of inertia (I) of the bicycle wheel about the axle, can be obtained graphically using the equation:
rm(g-a) = I(a/r)+Frictional Torque. Explain how to form two variables so that, I and Frictional Torque can be obtained from a linear graph. Identify the constants corresponding to the slope and intercept of the proposed linear graph.

r = 0.018m
m=0.200kg
g=9.8m/s^2
a=0.002812
I=?
Frictional Torque= ?
2. Relevant equations

(1) rm(g-a) = I(a/r)+Frictional Torque.

(2) y=mx+b

3. The attempt at a solution

Im not sure if im 100% right on this but, equation one could take the form of equation two.
m being I.
x being whats changing, ie. acceleration
b being the y intercept, ie frictional torque

Just unsure where to go from there a how to graph it.

Last edited by a moderator: Nov 18, 2014
2. Nov 19, 2014

### haruspex

Presumably these variable relate to a physical set-up of some kind. Please describe it.

3. Nov 20, 2014

### andrevdh

The two variables are m and a. Try and rewrite the equation so that they become the x and y variables in the linear equation (or a combination of the variables!). The frictional torque and moment of inertia should then part of gradient and y-intercept values (r and g will also appear in these).

Last edited: Nov 20, 2014