1. The problem statement, all variables and given/known data A 1.3 kg block is tied to a string that is wrapped around the rim of a pulley of radius 7.2cm. The mass of the pulley is 0.31kg. The block is released from rest. If the velocity of the block is 3.0m/s after it falls 0.5m, what is the moment of inertia for the pulley?[/b] 2. Relevant equations I = (1/2mv^2)/(angular velocity)^2 angular velocity = v/R 3. The attempt at a solution I= [(1/2)(1.3)(3.0)^2]/[(3.0/7.2)^2] I= 3.8025/0.1736 I= 21.90 I know this answer doesn't make sense, but I'm not sure what I'm missing. This was a test question I got wrong, so I'm not concerned about the answer, I just want to make sure I understand how to go about solving it to prepare for my final. Any help or guidance is greatly appreciated.