1. The problem statement, all variables and given/known data A right triangle has height 'h' and width 'b.' The right triangle has a constant area density. Calculate the moment of inertia of the triangle rotated around an axis that runs along side 'h.' 2. Relevant equations I = integral(r^2*dm) where 'r' is distance from the axis 3. The attempt at a solution equation of hypotenuse is (h/b) r^2 dm = r^2 * p * dA where p is area density and dA is the area of the rectangles. = r^2 * p * (h/b)r * dr = r^3 * p * (h/b) * dr --> integrate = ( (ph)/(3b) )r^3 with the limits of integration being from r=0 to r=b so: ( (ph)/3 )b^2 - 0 so I = ( (ph)/3 )b^2 But all my friends said I was wrong so can someone please tell me why?