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Moment of inertia of a square

  1. Jul 24, 2013 #1
    1. The problem statement, all variables and given/known data
    There are four masses (particles) with a mass of 30gr each and they are at the vertices of a square that has each side with a length of 90cm.
    What is the moment of inertia of this system through a perpendicular axis that is at the center of the square?


    3. The attempt at a solution
    My idea is to use the moment of inertia [itex]I = mr^{2}[/itex] (Point mass m at a distance r from the axis of rotation.)
    Then the distance will be the hypotenuse of a right triangle that has each side with 45cm and putting that into the moment of inertia and multiply by 4

    Is this correct?
     
  2. jcsd
  3. Jul 24, 2013 #2

    Filip Larsen

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    Gold Member

    Yes, that is correct.
     
  4. Jul 25, 2013 #3
    Thank you
     
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