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Homework Statement
I am trying to find the moment of inertia of a disc (let the mass be m and radius R) inclined at an angle θ to the vertical axis.
(See attachment 1)
Homework Equations
The Attempt at a Solution
I started by taking a small element of area dA. (see attachment 2)
The mass of this small element is dA*Mass density of disc.
dA=xd[itex]\phi[/itex]dx and mass density=m/([itex]\pi[/itex]R^2)
Now, moment of inertia is defined as
I=∫dmr^2 (Here r=xsinθ)
[tex]I=\int_{0}^{2\pi} \int_{0}^{R} \frac{m}{\pi R^2}xd \phi dx(x\sinθ)[/tex]
Solving this, i get
[tex]I=\frac{4}{3}mRsinθ[/tex] which i think is completely wrong.
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