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kk727
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Homework Statement
The flywheel of an engine has a moment of inertia 2.50 (kg)m^2 about its rotation axis.
What constant torque is required to bring it up to an angular speed of 400 rev/min in a time of 8.00s, starting from rest?Time (t) =8.00 sec
Ang Velocity (W) = 400 rev/min
Moment of Inertia (I) = 2.50 kg m^2
Homework Equations
W=Wo+αt
T = αI
The Attempt at a Solution
So, I converted the 400 rev/min to rad/sec.
400 * 2pi/60sec = 41.8876 rad/sec
I then plugged everything into the first equation to solve for angular acceleration.
41.8876 rad/sec = 0 + α(8 sec)
α = 5.2358 rad/sec^2
I then found torque using T=αI.
T=(5.2358)(2.50)
T=13.0895 N*m
Now, I thought that was the answer, so I tried looking up the question online to verify it. I found this:
http://answers.yahoo.com/question/index?qid=20101018171042AAmoOu0
I followed the same step process, but my only question is this -
From Yahoo Answers website...w (final) = w (initial) + (c) x time (t)
15pi= 0 + c(8.10x60seconds)
c= 0.0969
Why did that person multiply the time by 60 seconds? I did everything the same as them, except for this. Can someone explain why?