1. The problem statement, all variables and given/known data A thin rectangular slab, with dimensions 0.580 m by 0.830 m and mass 0.150 kg, is rotated about an axis passing through the slab parallel to the short edge. If the axis is 0.230 m from the short edge, what is the moment of inertia of the slab? 2. Relevant equations Ip=Icm+mh^2 3. The attempt at a solution So, I used the formula for inertia of a slap (I=1/12 x m x L^2) and plugged this in for Icm above: Ip=1/12 x M (L^2) + M x h^2 Ip=1/12 (.150)(.83^2)+.150(.230^2) Ip=.008611+.007935 Ip=.0165 But this wasn't correct, could you tell me where I went wrong?