A thin rectangular slab, with dimensions 0.580 m by 0.830 m and mass 0.150 kg, is rotated about an axis passing through the slab parallel to the short edge. If the axis is 0.230 m from the short edge, what is the moment of inertia of the slab?
The Attempt at a Solution
So, I used the formula for inertia of a slap (I=1/12 x m x L^2) and plugged this in for Icm above:
Ip=1/12 x M (L^2) + M x h^2
But this wasn't correct, could you tell me where I went wrong?