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## Homework Statement

A thin rectangular slab, with dimensions 0.580 m by 0.830 m and mass 0.150 kg, is rotated about an axis passing through the slab parallel to the short edge. If the axis is 0.230 m from the short edge, what is the moment of inertia of the slab?

## Homework Equations

Ip=Icm+mh^2

## The Attempt at a Solution

So, I used the formula for inertia of a slap (I=1/12 x m x L^2) and plugged this in for Icm above:

Ip=1/12 x M (L^2) + M x h^2

Ip=1/12 (.150)(.83^2)+.150(.230^2)

Ip=.008611+.007935

Ip=.0165

But this wasn't correct, could you tell me where I went wrong?