hello everyone ,, can someone tell me if I got the moment of inertia right or wrong of this question :
Two blocks of masses m1 = 5 kg and m2 = 15 kg are suspended from the ends of 1.5 m
rigid rod of weight 75 N that can rotate about point P, as shown in the figure. The rod is
held in a configuration such that it makes an angle of 37° with the vertical, and then
released. The two blocks can be considered as point particles and the moment of inertia
of the rod about its center of mass is I(com) = ML^2/12.
The Attempt at a Solution
I=I(com)+M(L/3)^2+m1(2L/3)^2+m2(L/3)^2 = (7/36)ML^2+(m2L^2/9)+(4m1L^2/9),, my teacher told me that adding m2 and m1 is wrong ,, but what i don't get ,, in some questions we add them ,, so is he right or wrong ??