A vehicle wheel has a mass 2.5 kg and diameter 310 mm. The vehicle moves from rest to a linear velocity of 13 kmh -1 in 60 s. Assuming that the wheel can be treated as a solid disc, find the torque applied to the wheel
Not so sure on how to add equations that aren't basic...
The Attempt at a Solution
I started with
0.5 x 2.5 x 0.1552 = 0.3003125
3.61ms-1 / 0.155 = 23.29 rads-1
23.29-0/60=0.388172043 (angular acceleration)
so then it should be
0.388172043 x 0.3003125 = 0.1165729167 Nm right?