1. The problem statement, all variables and given/known data There is a rod of length 0.5m, to the ends of which two finite point masses of 20g each (0.02 kg) each are attached. Find the moment of inertia along the axis passing through one end of the rod, neglecting the moment of inertia of the rod itself. 2. Relevant equations I=M*R^2 3. The attempt at a solution Since the Axis passes through one end, the moment of inertia is, I = 0.02*(0.5)^2+0.02*(0)^2 = 0.02* 0.25 = 0.005 = 5*10^(-3) But the answer given is twice the answer I've found (i.e. 10^(-2) ). In many similar questions, the answer is always twice what I get. Am I wrong or the answer printed is wrong? Thanks, Sleek.