Moment of inertia

  • #1
A uniform thin rod has a length 3.14 m and mass 2.11 kg. Find the moment of inertia in kg-m2 about an axis that is perpendicular to the rod and passes through the rod at a distance of 0.67 m from the end of the rod.

I know that if the axis was in the center of the rod the equation would be 1/12 * M *L^2 . M =mass L = length.

I don't know what to do with the axis being in a different place. is it the same eqation(doubt it) or the left half minus the right half or what?
 

Answers and Replies

  • #2
Pyrrhus
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Use the Parallel axis or Steiner's Theorem.
 
  • #3
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Have you heard of the Parallel Axis Theorem?
 
  • #4
Tide
Science Advisor
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Did you learn about the parallel axis theorem?
 
  • #5
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hahahahaha
 
  • #6
Tide
Science Advisor
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ECHO, Echo, echo!! ;)
 
  • #7
well thanks for the quick relpies, ummm yeah here in my book it is I = I(cm) +Mh^2

is I(cm) = 1/12 * M *L^2?
M is total mass
and h would be..... distance from the center of mass?
 
  • #8
2,209
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This is true.
 

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