- #1
ViewtifulBeau
- 50
- 0
A uniform thin rod has a length 3.14 m and mass 2.11 kg. Find the moment of inertia in kg-m2 about an axis that is perpendicular to the rod and passes through the rod at a distance of 0.67 m from the end of the rod.
I know that if the axis was in the center of the rod the equation would be 1/12 * M *L^2 . M =mass L = length.
I don't know what to do with the axis being in a different place. is it the same eqation(doubt it) or the left half minus the right half or what?
I know that if the axis was in the center of the rod the equation would be 1/12 * M *L^2 . M =mass L = length.
I don't know what to do with the axis being in a different place. is it the same eqation(doubt it) or the left half minus the right half or what?