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Moment of interia of apparatus

  • Thread starter noname1
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  • #1
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I need to calculate the moment of inertia of the setup below and i am confused.i have to initially calculate it without the point of masses and than with the point of masses. I have already calculated the acceleration for each of the experiments.


The info i have is:

Hanging mass - .050kg

Pulley Radius - .010m

Point of mass 1 - .250kg

Point of mass 2 - .250kg

Acceleration - 0.00671



I believe the moment of inertia of the bare arm is

I = mr²((g-a)/a)

I = .050*.010² * ((9.8-0.00671)/0.00671)

I = 0.000005 * 1459.51 = 0.0730

Am i calculating this correctly?

thanks in advance
 

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  • #2
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can anyone tell me if this is the way i should calculate it?
 

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