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Homework Help: Moment of interia of apparatus

  1. Mar 21, 2010 #1
    I need to calculate the moment of inertia of the setup below and i am confused.i have to initially calculate it without the point of masses and than with the point of masses. I have already calculated the acceleration for each of the experiments.


    The info i have is:

    Hanging mass - .050kg

    Pulley Radius - .010m

    Point of mass 1 - .250kg

    Point of mass 2 - .250kg

    Acceleration - 0.00671



    I believe the moment of inertia of the bare arm is

    I = mr²((g-a)/a)

    I = .050*.010² * ((9.8-0.00671)/0.00671)

    I = 0.000005 * 1459.51 = 0.0730

    Am i calculating this correctly?

    thanks in advance
     

    Attached Files:

  2. jcsd
  3. Mar 21, 2010 #2
    can anyone tell me if this is the way i should calculate it?
     
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