1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Moment of interia of apparatus

  1. Mar 21, 2010 #1
    I need to calculate the moment of inertia of the setup below and i am confused.i have to initially calculate it without the point of masses and than with the point of masses. I have already calculated the acceleration for each of the experiments.


    The info i have is:

    Hanging mass - .050kg

    Pulley Radius - .010m

    Point of mass 1 - .250kg

    Point of mass 2 - .250kg

    Acceleration - 0.00671



    I believe the moment of inertia of the bare arm is

    I = mr²((g-a)/a)

    I = .050*.010² * ((9.8-0.00671)/0.00671)

    I = 0.000005 * 1459.51 = 0.0730

    Am i calculating this correctly?

    thanks in advance
     

    Attached Files:

  2. jcsd
  3. Mar 21, 2010 #2
    can anyone tell me if this is the way i should calculate it?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Moment of interia of apparatus
Loading...