Moment problem-statics/physics

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The 10kN force is applied at point A. Determine the moment of F about point O.


I attached the image. I have a question regarding the sign. The direction of rotation is clockwise, wouldn't that mean the moment is (-)? The right-hand rule also points your thumb into the page which means it's negative. The book&solution manual, however, is saying that it is 16kN*m CW. Is the "CW" (clockwise) basically means you don't have to put the (-) sign? I'm confused. Does -16kN*m=16kN*m CW?
 

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  • #2
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The 10kN force is applied at point A. Determine the moment of F about point O.


I attached the image. I have a question regarding the sign. The direction of rotation is clockwise, wouldn't that mean the moment is (-)? The right-hand rule also points your thumb into the page which means it's negative. The book&solution manual, however, is saying that it is 16kN*m CW. Is the "CW" (clockwise) basically means you don't have to put the (-) sign? I'm confused. Does -16kN*m=16kN*m CW?

It is the samething as going 20MPH west equals going -20MPH east.
 

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