Could someone take a look at what I am working on and tell me if I am on the right track?(adsbygoogle = window.adsbygoogle || []).push({});

#1: Determine the moment of the 200 N force about point B. Please see attached picture for FBD.

First I find the x and y components.

x = 100N y= 173.2N, which are perpendicular and parallel to AB.

Then I find the distance of the 15° angle.

sin15(.5) = 0.13m

cos15(.5) = 0.48

So, now I add the forces to determine the moment about point B.

Mβ = +(173.2)(.48) - (100)(.13) = 70.1 N.M c.c.w

It would be of great appreciation is someone could help me.

Thank you.

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