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The weight of a uniform meter rule is 1.5N. Calculate the force exerted by the pivot on the meter rule.

The answer in the back of the book say it is magnitude of 0.5N downwards, I have tried every combo of equation from m=f*d to W=m*g

There are 3 question before, which I don't think are relevant to this question. Which I answers and got right. I have drawn a diagram to show what the meter rule looks like.

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