1. The problem statement, all variables and given/known data Two workers are moving a 20kg , 10m scaffolding pole. One stands at the end, the other stands 2.0m from the other end. Calculate the force exerted by the worker standing at the end in holding the pole. Assume the mass is distributed evenly and g = 9.8 m/s2. 2. Relevant equations Σclockwise = Σanticlockwise 3. The attempt at a solution 20kg * 9.8m/s2 = 196 N Taking the centre of the pole as pivot, one worker is 3m from the pivot and the other is 5m. Therefore: 3F1 = 5F2 With the mass distributed evenly, that's 2 kg/m through the pole. I don't know the rest, my teacher is making a habit of throwing us in the deep end without much instruction. I can see the point, though. Hope it pays off.