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Momentum after collision

  • Thread starter StotleD
  • Start date
21
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Let's say you throw a 3.5 kg lawn bowling ball forward (that is in the positive direction) at 12.3 m/s and it hits a 0.6 kg "pin" that is at rest. If the pin flies forward at 34.4 m/s, what is the ball's new velocity?
 

Answers and Replies

128
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StotleD said:
Let's say you throw a 3.5 kg lawn bowling ball forward (that is in the positive direction) at 12.3 m/s and it hits a 0.6 kg "pin" that is at rest. If the pin flies forward at 34.4 m/s, what is the ball's new velocity?
Just solve the following equation:

3.5*12.3 = 3.5v + 0.6*34.4
 
538
2
The total momentum before and after remains equal in absence of external forces , Equate the momenta before and after the event.

Initially : Ball's momentum with 'v' in positive sirection

Finally: PIN's momentum in positive direction+ Ball's mometum in negative x direction

Equate them.

BJ
 

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