1. The problem statement, all variables and given/known data A boulder that weighs 1500 kg is moving 10m/s in a Westerly direction, until it collides with a truck of mass 500kg travelling at 20m/s at a direction S30°W. After the collision the boulder moves away at 5m/s at a direction of S70°W. Find the speed and direction of the truck adter the crash. 2. Relevant equations 3. The attempt at a solution I tried sorting the problem into horizontal and vertical aspects. the horizontal equation looks like: 1500 * -10 + 500(-20 cos 60) = 1500 * (-5 cos 30°) + 500(v cos θ) which solves to: v cos = -34.38 where the 1500 and the 500 are the masses, the (-10) and (-5 cos 30) are the before the crash horizontal vectors, and (-20 cos 60) and (v cos θ) the after crash horiz vectors. the vertical equation: 1500 * 0 + 500(-20 sin 60) = 1500 * (-5 sin 30) + 500( v sin θ) which solves to: v sin θ = -9.82 where 1500 and 500 are the masses again, (0) and (-20 sin 60) the before the crash vertical components, andd (-5 sin 30) & (v sin θ) the after the crash components. from here i tried: tan θ = -34.38 / -9.82 θ = 0.061 but im fairly certain this is wrong. Can anyone please tell me where i went wrong? thank you!