Question: A stream of water from a hose is hitting a window. The window is vertical, the stream is horizontal, and the water stops when it hits. About 20cm(cubed), that is 20g, of water with speed 1.5 m/s strikes the window each second. Find a) the impulse on the window in time t and b) the force exerted on the window.
I= delta p = mv -mu = Ft
f= delta p/t = mv-mu/t
s=ut +1/2 at (the last t is squared)
The Attempt at a Solution
well i originally tried to split this problem up into it vertical and horizontal components, saying that the water would follow a hyperbelar (i forget how to spell it) shape.
then i used the s=ut for the horizontal component (the rest of the equation isn't needed as the water doesnt accelerate horizontally and therefore is a 0 value) but then found that s and t arnt known.
i have a feeling it has something to do with the 20g of water with a force of 1.5m/s every second but i dont know what to do!
please help :)