Bead Momentum and Collisions

In summary, the conversation discusses the concept of momentum and its application in a collision between two beads. The equation of conservation of linear momentum is mentioned and it is noted that this holds true for all collisions, regardless of whether they are elastic or not. The difference between elastic and inelastic collisions is also explained. The equation x=1/2(vi+vf)t is mentioned but it is noted that it may not be applicable in this case due to the absence of external forces and acceleration.
  • #1
sfzpilot
3
0
A 0.400 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The bead collides elastically with a larger 0.600 kg bead initially at rest. After the collision, the smaller bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along the wire in the first 5.0 seconds following the collision.

I am not sure how to do this. I know to change the cm/s to m/s but not sure what equation to use. Any help is appreciated. Thanks!
 
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  • #2
You seem to know that it's about momentum. What happens to momentum during the collision?
 
  • #3
Well since I know that Momentum=mass x velocity, the mass stays the same but velocity goes down. Therefore, the momentum goes down. But I am not sure on how that all fits into the distance.
 
  • #4
Have you learned about conservation of linear momentum?
 
  • #5
Yes I have learned about them. I have learned about the elastic collision (m1v1+m2v2=m1v1'+m2v2') and also Interlastic (m1v1+m2v2=(m1+m2)v')
I have an equation x=1/2(vi+vf)t. But that seems too easy.
 
  • #6
It is true that x = 1/2(vi + vf)t for constant acceleration. In this case, however, is there any acceleration or force on either bead after the collision? Would anything happen to the velocity of either bead after the collision (remember the wire is frictionless)?

The equation that you wrote down,

[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}[/tex]

is conservation of linear momentum when there is no external force on the two masses (i.e. the system). This holds true, when there is no external force, for all collisions whether they are elastic or not, so try to use this to solve your problem. Remember that velocity is sign sensitive.

For future reference, the difference between elastic and inelastic collisions is that elastic collisions preserve not only linear momentum but total kinetic energy in the colliding objects. Inelastic collisions lose some of that kinetic energy during the collision, usually as heat or sound. All real collisions are at least a bit inelastic since some energy is always lost. The type of inelastic collision you may be thinking of is when two objects stick together after they collide, like a car crash, in which both cars were moving before the accident (had kinetic energy), but are clearly not moving after the crash (lost kinetic energy).
 

1. What is bead momentum?

Bead momentum is a measure of the quantity of motion an object has. Specifically, it is the product of an object's mass and its velocity.

2. How is bead momentum conserved in collisions?

In collisions, the total momentum of the system (all objects involved) remains constant. This means that the initial momentum of the beads before the collision is equal to the final momentum of the beads after the collision.

3. What is the difference between elastic and inelastic collisions?

In elastic collisions, the total kinetic energy of the system is conserved, meaning that the beads bounce off each other and there is no loss of energy. In inelastic collisions, some of the kinetic energy is converted into other forms, such as heat or sound, resulting in a decrease in the total kinetic energy of the system.

4. How does mass affect bead momentum in collisions?

The mass of an object is directly proportional to its momentum. This means that a heavier bead will have a greater momentum than a lighter bead moving at the same velocity.

5. Can bead momentum be negative?

Yes, bead momentum can be negative if the direction of motion is in the negative direction. This simply means that the object is moving in the opposite direction as the positive direction chosen for the system.

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