A small block of mass m1 = 0.300 kg is released from rest at the top of a curved wedge of mass m2 = 2.00 kg, which sits on a frictionless horizontal surface as in Figure P6.59a. When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right, as in Figure P6.59b.(adsbygoogle = window.adsbygoogle || []).push({});

(a) What is the velocity of the wedge after the block reaches the horizontal surface?

I found the velocity to be -.6 m/s. I did 0=m2v2 + M(block)V(block)

(b) What is the height h of the wedge?

I dont know how to get the height of the wedge, please help

I know the energy equation will be

mgh= .5mv^2

Please help

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# Homework Help: Momentum and Energy- Major help needed

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