1. The problem statement, all variables and given/known data A bullet of mass 0.03kg is fired from a gun with a horizontal velocity of 400 ms^-1. Find the momentum of the bullet after it is fired. If the gun is then brought to rest in 1.2s by a horizontal force which rises uniformly from zero to B N and then falls uniformly to zero, find the value of B. 2. Relevant equations Impulse = force * time. 3. The attempt at a solution Momentum of the bullet = 0.03 * 400 = 12 kg ms^-1, taking the direction of the bullet to be positive. So momentum of the gun is also 12 kg ms^-1. Now, the problem, my friends have all jumped in and said as I = ft, then 12 = F*1.2, so F = 10 N. Why is this? How have we gone from the information given about rising uniformly to B and then back again, to just using that equation? Also, why is the impulse just the same as the momentum? Also, I was thinking, don't we need to double this? Is 10 N not the force to rise up, and the same is needed to come back down? Hope this post makes sense, thanks for help.