1. A 10g bullet moving at 1000m/s collides inelastically with a 30 kg wooden block at rest. The block is 20 cm thick and can slide freely on a frictionless table. After fully penetraing the block, the bullet comes to rest within the block. a) calculate the time required for the bullet to penetrate the box. b) Find the average force exerted by the bullet on the block during impact. 2. impact time= 2(impact distance)/impact velocity, mv=mv, v=v0 + at, x=x0 +v0t + .5at^2 3. (a) I tried imputing it into the 1st equstion. the impact distance is 20cm and the impact velocity is 1000m/s and i got 0.0004 secs. (b) favg= delta P/impact time. so i did (mvfinal - mvinitial)0.0004 secs. I got [0-(0.01)(10000)]/(0.0004 secs) and then i got -25,000N. THANKS!