- Homework Statement:
A man stands on a trolley that is free to move on a horizontal surface and subject to no
resistance forces. The mass of the man is 70 kg and the mass of the trolley is 10 kg.
He has two sandbags, each of mass 20 kg, on the trolley with him. Initially, the trolley
and the man are at rest.
(a) The man throws one bag off the trolley, and after this the trolley moves at a constant
velocity. The bag is thrown so that it has a horizontal velocity of 2 m/s. Find the speed
of the trolley, man and the remaining bag.
(b) After the first bag has been thrown, the man then throws the second bag, in the same
direction as the first. Immediately after the bag is thrown, it has a horizontal velocity
of 2 m/s relative to the trolley. Find the speed of the trolley and the man after the
second bag has been thrown.
- Relevant Equations:
- m1v1 +m2v2 = m1v3 + m2v4
I am having trouble with part b). I found the answer to part a) is -0.4 and for part b) the mark scheme says that the velocity of the 2nd bag is 1.6m/s but how do I find that out? If someone could perhaps show step-by-step of part b)?