1. The problem statement, all variables and given/known data A bullet(mass 100 g) strikes a block of 4 kg kept on a table. The friction coefficient of table-block is 0.25. The bullet gets embedded and moves a distance of 20 m. Find speed of bullet. 2. Relevant equations 3. The attempt at a solution Using Conservation of momentum, speed of block + bullet= v/401 (v is the speed of the bullet) now equating Energy; Work one by friction = kinetic energy of system 0.25*4.01*10*20=0.5*4.01*(v/401)^2 v=4010 am i right?