Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

MOMENTUM, contact time, need help

  1. Mar 13, 2005 #1
    A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s

    Pf = mvf = (50 x 10^-3 kg) (44 m/s) = 2.2 kg m/s

    From this I must find the contact time t = change in x /average velocity

    The change in x in the radius of the ball .05m

    The average velocity provided in the solution is 22 m/s

    I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s

    Help anyone
  2. jcsd
  3. Mar 13, 2005 #2
    Where did you get the change in x is .05 m? That information wasn't given to you in the problem... is
    all you were given?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook