A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s(adsbygoogle = window.adsbygoogle || []).push({});

Pf = mvf = (50 x 10^-3 kg) (44 m/s) = 2.2 kg m/s

From this I must find the contact time t = change in x /average velocity

The change in x in the radius of the ball .05m

The average velocity provided in the solution is 22 m/s

I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s

Help anyone

**Physics Forums - The Fusion of Science and Community**

# MOMENTUM, contact time, need help

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: MOMENTUM, contact time, need help

Loading...

**Physics Forums - The Fusion of Science and Community**