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Momentum Explosion Question

  1. Feb 15, 2010 #1
    1. The problem statement, all variables and given/known data

    An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. the heavier fragment slides 8.2m before stopping. how far does the lighter fragment slide? Assume that both fragments have the same coefficient of kinetic friction.



    2. Relevant equations

    0 = mv1 + mv2


    3. The attempt at a solution

    The initial momentum is 0 in this question because there is no movement initially.
    using the equation 0 = mv1 + 7mv2

    -mv1 = 7mv2
    -v1 = 7v2

    but... the problem im having is how do i incorporate the distance ?
    help!
     
  2. jcsd
  3. Feb 16, 2010 #2
    you can use vi power 2 -vi 0power 2=2ax and calculate accelerate then use again this formulla to find the distance of lighter mass.
     
  4. Feb 17, 2010 #3
    what do you mean. how do you find the acceleration?
    that equation vf^2 = vi^2 + 2ad has 2 unknowns, therefore it cannot be solved to find the acceleration...

    could anyone explain how i can solve the problem ?
     
  5. Feb 17, 2010 #4

    collinsmark

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    Gold Member

    I believe you can solve this by recognizing the relationship

    [tex] E = \int _a ^b \vec F \cdot \vec ds [/tex]

    But don't worry, you don't have to really do any calculus. Since the frictional forces can be approximated as constants, the above equation reduces to

    [tex] E = \vec F \cdot \vec s [/tex]

    where [tex] E [/tex] is the energy, [tex] \vec F [/tex] is the frictional force, and [tex] \vec s [/tex] is the displacement (i.e. distance) traveled.

    Start with the heavier fragment. Calculate its normal force and multiply it by the coefficient of friction to get the frictional force. Use that, and the equation above, to determine the energy converted to frictional heat, associated with the heavier fragment (hint: this is where the 8.2 m comes into play, together with the frictional force which you just calculated).

    Now you can use (1/2)mv2 to get the initial velocity of the heavier fragment. Once you know the heavier fragment's velocity you can express its momentum.

    Now you can move on to the lighter fragment. Conservation of momentum means that the lighter fragment will have the same initial momentum magnitude as the heavier fragment, but in the opposite direction. If you know its initial momentum, you can calculate its initial velocity (you already know that the mass is 1/7 that of the heavier object, and you know its momentum, so you can solve for velocity). You can also calculate its normal force, and thus its frictional force, and also its initial kinetic energy. That's all the information you need to use in the above equations to calculate its sliding distance.
     
    Last edited: Feb 17, 2010
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