- #1
lando45
- 84
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Hey,
I have been set this question and I'm half-way through answering it but am stuck on where to go next...here's the question:
The m1 = 1.1 kg block at rest on a horizontal frictionless surface is connected to an unstretched spring (k = 180 N/m) whose other end is fixed. (See Fig. 10-36.) The m2 = 2.2 kg block whose speed is 4.0 m/s collides with the 1.1 kg block. Assume that the two blocks stick together after the one-dimensional collision. What maximum compression of the spring occurs when the blocks momentarily stop?
Using m1v1 = m2v2 I got:
2.2 x 4.0 = 8.8kg/m/s
The joint mass of the two blocks is 3.3kg so the velocity must be 2.66m/s
But I don't understand how to calculate the spring compression knowing only the velocity and the "k" value of the spring?
Any help appreciated,
Thanks
I have been set this question and I'm half-way through answering it but am stuck on where to go next...here's the question:
The m1 = 1.1 kg block at rest on a horizontal frictionless surface is connected to an unstretched spring (k = 180 N/m) whose other end is fixed. (See Fig. 10-36.) The m2 = 2.2 kg block whose speed is 4.0 m/s collides with the 1.1 kg block. Assume that the two blocks stick together after the one-dimensional collision. What maximum compression of the spring occurs when the blocks momentarily stop?
Using m1v1 = m2v2 I got:
2.2 x 4.0 = 8.8kg/m/s
The joint mass of the two blocks is 3.3kg so the velocity must be 2.66m/s
But I don't understand how to calculate the spring compression knowing only the velocity and the "k" value of the spring?
Any help appreciated,
Thanks