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Momentum help.

  1. Feb 22, 2009 #1
    I need help with this problem where we are suppose to determine the fraction of kinetic energy lost by a neutron m=1.01u when it collides head-on and elastically with a target particle at rest which is.

    examples used..
    Hydrogen = 1.01u
    heavy hydrogen = 2.01u

    How would you do this?
    Do we use .5MaV^2 +.5MbV^2 = .5Ma'V^2 + .5Mb'V^2 + energy loss?


    examples used..
    Hydrogen = 1.01u
    heavy hydrogen = 2.01u

    Thanks again,
     
  2. jcsd
  3. Feb 22, 2009 #2
    hello,
    such questions can be solved using Conservation Of Momentum,and Work Energy theorem(that you used)

    1st derive a relation between velocities of masses(call [tex]v_1\ and\ v_2[/tex])

    then use the equation you are using


    thanks
     
    Last edited: Feb 22, 2009
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