:yuck: I have this problem that I'm not sure I am on the right track. The problem is A .20 kg billiard ball traveling at a speed of 15m/s strikes the side rail of the pool table at an angle of 60 degrees. If the ball rebounds at the same speed and angle, what is the cahnge in its momentum.(adsbygoogle = window.adsbygoogle || []).push({});

I have the following formulas:

∆p=p2-p1 = ∆px + ∆py

∆px = p2x-p1x 2pcos θ

∆py = p2y – p1y = p2sin θ – p1 sin θ = 0

So, if I calculate p = mv I get .3kg*m/s

Do I plug that value in for p in the equations above, and then I'm not sure what to do with the ∆py equation.

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# Homework Help: Momentum homework problem

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