1. The problem statement, all variables and given/known data A particla of charge q enters a region of uniform magnetic field B (pointing into the page). The field deflects the particle a distance d above the original line of flight. In terms of a, d, B, and q, find the momentum of the particle. 2. Relevant equations F=dp/dt Fmag=(vXB)q I put v=vy and B=-Bx 3. The attempt at a solution I started by setting the two above equations equal to eachother. dp/dt=(vXB)q I took the cross product and got dp=Bvqzdt and since v=ds/dt dp=Bq(ds)z and since the displacement was from when the particle entered the field to when it would be leaving, I said it went from 0 to a and p=Bqaz This is the answer I got but I was just concerned because it didn't include the value that the particle was vertically displaced by the magnetic force, d. Is this answer right, or does the vertical displacement appear somewhere that I've overlooked? EDIT: I just remembered that the direction of the velocity changes because of the magnetic force. So instead of the displacement being just a wouldn't it now be √(a2+d2 ?